Question

fórmula de bhaskara
③ resolva
a) x² - 5x+6=0(2,3)
b) x ² - 5x+8=0 (0)
c) 4 x ² - 8 8+4=0 (1,1)​

Answer 1

Resposta:

a) a= 1; b= -5; c= 6

∆= b²-4a.c

∆= (-5)²-4.1.6

∆= 25-24

∆=1

$x1= \frac{ 5 + 1}{2}$

$x1 = \frac{6}{2}$

$x1 = 3$

$x2 = \frac{5 - 1}{2}$

$x2 = \frac{4}{2}$

$x2 = 2$

b) a=1; b= -5; c= 8

∆= (-5)²-4.1.8

∆= 25 - 32

∆= -7

(não existe raiz)

c)a= 4; b= -8; c=4

∆= (-8)²-4.4.4

∆= 64- 64

∆= 0

$x1 = \frac{8 + 0}{8}$

$x1 = \frac{8}{8}$

$x1 = 1$

$x2 = \frac{8 - 0}{8}$

$x2 = \frac{8}{8}$

$x2 = 1$