Question

5) Considere a função f(x) = 5x² +160x +1280. Determine o vértice.

Answer 1

Resposta:

Explicação passo-a-passo:

Xv= -b/2a

Xv= -160/10

Xv= -16

Yv= (4ac -b²) /4a

Yv= (4*5*1280-160²)/4*5

Yv= 25600 -25600/20

Yv= 0/20

Yv= 0

vértice ( -16, 0 )