Question

qual é a derivada de $\frac{2}{\sqrt[2]{x} } - \frac{1}{x}$

Answer 1

Explicação passo-a-passo:

$\sf f(x)=\dfrac{2}{\sqrt{x}}-\dfrac{1}{x}$

$\sf f(x)=2\cdot x^{\frac{-1}{2}}-x^{-1}$

$\sf f'(x)=2\cdot\left(\dfrac{-1}{2}\right)\cdot x^{\frac{-1}{2}-1}-(-1)\cdot x^{-1-1}$

$\sf f'(x)=-x^{\frac{-3}{2}}+x^{-2}$

$\sf f'(x)=\red{-\dfrac{1}{\sqrt{x^3}}+\dfrac{1}{x^2}}$