Question

pfvr, com TODAS as passagens

Answer 1

Resposta:

$\sf \dfrac{6x - 2}{3} - \dfrac{8x- 3}{4} = x + \dfrac{2x + 5}{3} \quad \gets \text{\sf O m.m.c de \{3 ; 4\} = 12 }$

$\sf \dfrac{4\cdot (6x - 2)}{12} - \dfrac{3 \cdot(8x- 3)}{12} = \dfrac{12x}{12} + \dfrac{4\cdot(2x + 5)}{12} \quad \gets \text{\sf Cancelar o denominador 12 }$

$\sf 4\cdot (6x - 2) - 3\cdot (8x - 3) = 12x + 4 \cdot (2x +5) \quad \gets \text{ \sf Multiplicar e eliminar os parentes.}$

$\sf 24x - 8 -24x + 9 = 12x +8x + 20$

$\sf 1 = 20x + 20$

$\sf 20x + 20 = 1$

$\sf 20x = 1 - 20$

$\sf 20x = - 19$

$\boxed{ \boxed{ \boldsymbol{ \sf x = - \dfrac{19}{20} }}} \quad \Longleftarrow \mathbf{ Resposta }$

Explicação passo-a-passo: