Question

Faça a soma de f(-2), f(-1), f(0), f(1) e f(2) na função f(x) = 8x² - 7x + 3

Answer 1

Explicação passo-a-passo:

f(x) = 8x² - 7x + 3

1)

f(-2) = 8.(-2)² - 7.(-2) + 3

f(-2) = 8.4 + 14 + 3

f(-2) = 32 + 14 + 3

f(-2) = 49

2)

f(-1) = 8.(-1)² - 7.(-1) + 3

f(-1) = 8.1 + 7 + 3

f(-1) = 8 + 7 + 3

f(-1) = 18

3)

f(0) = 8.0² - 7.0 + 3

f(0) = 0 + 0 + 3

f(0) = 3

4)

f(1) = 8.1² - 7.1 + 3

f(1) = 8.1 - 7 + 3

f(1) = 8 - 7 + 3

f(1) = 4

5)

f(2) = 8.2² - 7.2 + 3

f(2) = 8.4 - 14 + 3

f(2) = 32 - 14 + 3

f(2) = 21

Logo:

f(-2) + f(-1) + f(0) + f(1) + f(2) = 49 + 18 + 3 + 4 + 21

f(-2) + f(-1) + f(0) + f(1) + f(2) = 95

Answer 2

Resposta:

$f( - 2) = 8 \times {( - 2)}^{2} - 7 \times ( - 2) + 3 \\ f( - 2) = 8 \times 4 + 14 + 3 \\ f( - 2) = 32 + 14 + 3 \\ f( - 2) = 46 + 3 \\ f( - 2) = 49$

$f(- 1) = 8 {( - 1)}^{2} - 7 \times ( - 1) + 3 \\ f( - 1) = 8 + 7 + 3 \\ f( - 1) = 15 + 3\\ f( - 1) = 18$

$f(0) = 8 \times {0}^{2} - 7 \times 0 + 3 \\ f(0) = 0 - 0 + 3 \\ f(0 ) = 3$

$f(1) = 8 \times {1}^{2} - 7 \times 1 + 3 \\ f(1) = 8 - 7 + 3 \\ f(1) = 4$

$f(2) = 8 \times {2}^{2} - 7 \times 2 + 3 \\ f(2) = 8 \times 4 - 14 + 3 \\ f(2) = 32 - 14 + 3 \\ f(2) = 18 + 3 \\ f(2) = 21$

soma:49+18+3+4+21= 95