Question

k) 3x2 – 2x - 1 = 0​

Answer 1

Resposta:

Explicação passo-a-passo:

$3x^2 - 2x - 1 = 0$

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Discriminante delta Δ

Δ = b² − 4ac

Δ = (−2)² −4⋅(3)⋅(−1)

Δ = 4 +

Δ = 16

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$x = \dfrac{-b \pm \sqrt{\triangle}}{2a} \\ \\ \\x = \dfrac{-(-2) \pm \sqrt{16}}{2.3} \\ \\ \\ x = \dfrac{2 \pm 4}{6} \\ \\ \\ x = \dfrac{2 + 4}{6} \\ \\ \\ x' = \dfrac{6}{6} \\ \\ \\ x' = 1 \\ \\ \\ \\x'' = \dfrac{2 - 4}{6} \\ \\ \\ x'' = \dfrac{-2}{6} \\ \\ \\x'' = \dfrac{-1}{3} \\ \\\\\\\\S = ( 1 , ~~\dfrac{-1}{3} )$

Answer 2

Bom Dia !!!

utilizamos fórmula de bháskara.

a = valor com x²

b = valor seguido de x

c = sozinho

$a = 3\\b=-2\\c=-1$

Δ = $b^{2} -4.a.c$

Δ = $4-4.3.(-1)$

Δ = 4 + 12

Δ = $16$

$\frac{-b-+\sqrt{16} }{2.a}$

$\frac{2-+4}{6}$

x¹ = $\frac{6}{6}$

x¹ = 1

x² = $\frac{-2}{6}$

x² = $-\frac{1}{3}$

s = {1, $-\frac{1}{3}$}

Espero ter ajudado :-)

Att: LDC