Question

×-5×+6=0
$x {}^{2} - 5x + 6 = 0$
​

Answer 1

Vamos lá.

x²-5x+6=0

delta= b²-4*a*c = (-5)²-4*1*6 = 1

x= -b±√delta / 2*a = -(-5)±√1 / 2*1 = 5±1 / 2

x'= 5+1 / 2 = 3

x"= 5-1 / 2 = 2

Answer 2

$\large \text{ \sf{x {}^{2} - 5x + 6 = 0 } }$

$\large \text{ \sf{ \begin{cases} \sf a = 1 \\ \sf b = - 5 \\ \sf c = 6\end{cases} } }$

$\large \sf{\Delta=b^2-4\cdot a\cdot c }$

$\large \sf{\Delta=(-5)^2-4\cdot1\cdot6 }$

$\large \sf{\Delta=25-24 }$

$\large \sf{ \Delta=1}$

$\large \text{ \sf{x= \dfrac{-b\pm \sqrt{\Delta}}{ 2\cdot a}} }$

$\large \text{ \sf{ x = \dfrac{ - ( - 5) \pm \sqrt{1} }{2 \cdot1} } }$

$\Large \text{ \sf{ x = \dfrac{5 \pm1}{2} \begin{cases} \sf x _{1} = \dfrac{5 + 1}{2} = \dfrac{6}{2} = 3 \\ \\ \sf x _{2} = \dfrac{5 - 1}{2} = \dfrac{4}{2} = 2\end{cases}} }$