• Matéria: Matemática
  • Autor: igorcaue317
  • Perguntado 5 anos atrás

Qual o perímetro da figura abaixo? *
Imagem sem legenda
53a³b³
30a²b³
38ab³
42ab³
40ab³​

Anexos:

Respostas

respondido por: kljcjkacbhkcbhncbh
0

TEM 2 FORMAS DE FAZER ESSA CONTA:

1 FORMA:

53a^3b^{330}a^2b^{338}ab^{342}ab^{340}ab^3:\quad 53a^8b^{1353}\\\\\\53a^3b^{330}a^2b^{338}ab^{342}ab^{340}ab^3\\\\\\53a^{3+2+1+1+1}b^{330}b^{338}b^{342}b^{340}b^3\\\\\\53a^8b^{330}b^{338}b^{342}b^{340}b^3\\\\\\53a^8b^{330+338+342+340+3}\\\\\\53a^8b^{330+338+342+340+3}

53a^8b^{1353}

OU

2 FORMA:

53a^3b^{330}a^2b^{338}ab^{342}ab^{340}ab^3:\quad 53a^8b^{1353}\\\\\\53a^3b^{330}a^2b^{338}ab^{342}ab^{340}ab^3\\\\\\a^3a^2aaa=a^{3+2+1+1+1}\\\\\\53a^{3+2+1+1+1}b^{330}b^{338}b^{342}b^{340}b^3\\\\\\b^{330}b^{338}b^{342}b^{340}b^3=b^{330+338+342+340+3}\\\\\\53a^8b^{330+338+342+340+3}\\\\\\330+338+342+340+3=1353\\\\\\53a^8b^{1353}

RESPOSTA : 53a^{8}  b^{1353}

espero ter ajudado


kljcjkacbhkcbhncbh: mas eu prefiro que vc fassa a 1 forma
igorcaue317: bl
igorcaue317: obg
kljcjkacbhkcbhncbh: por nada
igorcaue317: pode me ajudar em mais algumas
kljcjkacbhkcbhncbh: claro
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