Question

o numero complexo (1+i)^18 é:
a) -512
b) 2i
c) -512i
d) 512i
e) 512

Answer 1

(1+i)² = 1 + 2i + i² = 1 + 2i - 1 = 2i

(1+i)¹⁸ =

[(1+i)²]⁹ = [2i]⁹ = 2⁹.i⁴.i⁴.i¹ = 512.1.1.i = 512i ✓