Question

(-0,25)+(-1\10)-(-3\5)+(-1\8)= Obs; Esponham a conta . 0\0=fraçao

Answer 1

Para somar
 1° pôr todos os números na forma fracionária
 2° retirar parentes
 3° dar comum denominador (mmc ou outro método)
 4° efetuar soma pelo procedimento convencional

             $(-0,25)+(- \frac{1}{10})-(- \frac{3}{5})+(- \frac{1}{8} ) \\ \\ = -\frac{25}{100} - \frac{1}{10} + \frac{3}{5} - \frac{1}{8} \\ \\ =- \frac{1}{4} - \frac{1}{10} + \frac{3}{5} - \frac{1}{8} \\ \\ = \frac{-10-4+24-5}{40} \\ \\ = \frac{5}{40} \\ \\ = \frac{1}{8}$

Answer 2

$(-0,25)+\left( -\dfrac{1}{10} \right)-\left( -\dfrac{3}{5} \right)+\left( -\dfrac{1}{8} \right)\to\\\\\\ \left( -\dfrac{25}{100} \right)+\left( -\dfrac{1}{10} \right)-\left( -\dfrac{3}{5} \right)+\left( -\dfrac{1}{8} \right)\to\\\\\\ -\dfrac{25}{100} -\dfrac{1}{10}+\dfrac{3}{5} -\dfrac{1}{8}\to\\\\\\ -\dfrac{1}{4} -\dfrac{1}{10}+\dfrac{3}{5} -\dfrac{1}{8}\to~~mmc=40\\\\\\ \dfrac{-10-4+24-5}{40} \to\\\\\\ \dfrac{-19+24}{40} \to \\\\\\\dfrac{5}{40} \to\\\\\\ \large\boxed{\dfrac{1}{8}~~ou~~1,125}$