Question

Considerando que o log 3 = 0,48 e log 2 = 0,30. Determine:

a) log 36

b) log 4,5

ME AJUDEM POR FAVOR

Answer 1

Explicação passo-a-passo:

a)

$\sf log~36=log~(2^2\cdot3^2)$

$\sf log~36=log~2^2+log~3^2$

$\sf log~36=2\cdot log~2+2\cdot log~3$

$\sf log~36=2\cdot0,30+2\cdot0,48$

$\sf log~36=0,60+0,96$

$\sf \red{log~36=1,56}$

b)

$\sf log~4,5=log~\left(\dfrac{9}{2}\right)$

$\sf log~4,5=log~9-log~2$

$\sf log~4,5=log~3^2-log~2$

$\sf log~4,5=2\cdot log~3-log~2$

$\sf log~4,5=2\cdot0,48-0,30$

$\sf log~4,5=0,96-0,30$

$\sf \red{log~4,5=0,66}$