Question

Escreva os 3 primeiros termos da seqüência definida por:
a 1 = 2 e a n+1 = a n + 8

Answer 1

$solve\:for\:a,\:a\cdot \:1=2ean+1\cdot \:an+8\quad :\quad a=\frac{8}{1-2en-n};\quad \:n\ne \frac{1}{2e+1}\\\\\\a\cdot \:1=2ean+1\cdot \:an+8\\\\\\a=2ean+1\cdot \:an+8\\\\\\\\a=2ena+na+8\\\\\\\\a-\left(2ena+na\right)=2ena+na+8-\left(2ena+na\right)\\\\\\\\a-2ena-na=8\\\\\\\\a-2ena-na=8\\\\\\a\left(1-2en-n\right)=8\\\\\frac{a\left(1-2en-n\right)}{1-2en-n}=\frac{8}{1-2en-n};\quad \:n\ne \frac{1}{2e+1}\\\\\\a=\frac{8}{1-2en-n};\quad \:n\ne \frac{1}{2e+1}$