Question

a distancia entre A (_1,4)e B(3,2).

Answer 1

$d^{2}ab$=($(xb-xa)^{2} + (yb-ya)^{2}$
$d ^{2} ab=(3-(-1)) ^{2} + (2-4) ^{2}$
$d^{2} ab=( 4 )^{2}+(-2) ^{2}$
$d^{2}ab= 16+4$
$d^{2} ab=20$
$dab= \sqrt{20}$
$dab=2 \sqrt{5}$

Logo, a distancia de A ate B e igual a $2\sqrt{5}$