• Matéria: Matemática
  • Autor: salletec67
  • Perguntado 9 anos atrás

Me ajudem por favor , preciso da conta montada

Anexos:

Respostas

respondido por: Anônimo
1

Salete,
Ajudo com a primeira

a)
            Area do losango = (D x d) /2
                      D = 12
                       d = 4√7
                               as diagonais se cortam em angulo reto
                               forma 4 triângulos retos iguais onde
                                         D/2 = cateto
                                         d/2 = cateto 
                                             l = hipotenusa
                               então
                                            cateto 1 = 12/2 = 6
                                            cateto 2 = d/2
                                            hipotenusa = 8
                                                  8^2 = 6^2 + (d/2)^2
                                                   64 = 36 + d^2/4
                                                   (64 - 36)x4 = d^2
                                                        d^2 = 112
                                                          d = √112
                                                          d = 4√7
          A = (12 x 4√7)/2
                                      A = 24√7 cm²

salletec67: muito obrigado Pancho ☺️
Anônimo: Por nada. Bons estudos!!
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