• Matéria: Lógica
  • Autor: isadoraaraujo12
  • Perguntado 5 anos atrás

resolva
a) m.m.c. (6, 8, 12) =
g) m.m.c. (28, 42)
b) m.m.c. (2, 14, 21) =
h) m.m.c. (3, 12, 18) =
c) m.m.c. (4, 6, 12) =
i) m.m.c. (5, 15, 25) =
d) m.m.c. (36, 48) =
j) m.m.c. (8, 16, 32) =
e) m.m.c. (50,75) =
m.m.c. (8, 9, 15)
f) m.m.c. (3, 12, 15)

Respostas

respondido por: Anne0961
4

Resposta:

a) 6, 8, 12 | 2\\3, 4, 6 |2\\3, 2, 3| 2\\3, 1, 3|3\\1, 1, 1| 2^{3} .3= 24

g)28, 48| 2\\14, 24| 2\\7, 12| 2\\7, 6 | 2\\ 7, 3|3\\  7, 1|7\\  1, 1| 2^{4}.3.7=336

b)2, 14, 21|2\\1, 7, 21| 7\\1, 1, 3| 3\\1, 1, 1| 2.7.3=42

h)3, 12, 18|2\\3, 6, 9|3\\1, 2, 3|3\\1, 2, 1| 2\\1, 1, 1| 2.2.3.3=36

c)4, 6, 12|2\\2, 3, 6|2\\1, 3, 3|3\\1, 1, 1|2.2.3=12

i)5, 15, 25| 5\\1, 3, 5|5\\1, 3, 1|3\\1, 1, 1|5.5.3=75

d)36, 48|2\\18, 24|2\\9, 12| 2\\9, 6| 2\\9, 3| 3\\3, 1| 3\\1, 1|2^{4} .3^{2}=144

j) 8, 16, 32|2\\4, 8, 16|2\\2, 4, 8|2\\1, 2, 4|2\\1, 1, 2|2\\1, 1, 1|2^{5} =32\\

e)50, 75|5\\10, 15|5\\2, 3|2\\1, 3| 3\\1, 1| 5.5.2.3=150\\

8, 9, 15|2\\4, 9, 15|2\\2, 9, 15|2\\1, 9, 15|3\\1, 3, 5|3\\1, 1, 5| 5\\1,1,1|2^{3} .3^{2} .5=360

f)3, 12, 15|3\\1, 4, 5|2\\1, 2, 5|2\\1, 1, 5|5\\1, 1, 1| 3.2.2.5=60

O número após o traço está dividindo os anteriores e quando resta somente 1, 1, 1, multiplica-se os divisores.

Espero ter ajudado ^-^

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