Question

dada a função y = -x² - 10x . calcule a coordenada do vértice

Answer 1

Resolução. ∆ = b^2 - 4 * a * c ∆ = (-10)^2 - 4 * (-1) * 0 ∆ = 100 - 0 ∆ = 100 Xv = -b / 2a = 10 / -2 = -5 Yv = -∆ / 4a = -100 / -4 = 25 V ( Xv , Yv ) = ( -5 , 25 ) Espero ter ajudado, valeu.

Answer 2

Aplicar as relações correspondentes

                xV = - b/2a
                     = 10/2(-1)
                                                  xV = - 5
                yV = - Δ/4a
                          Δ = b^2 - 4.a.c
                             = (-10)^2 - 4(-1)(0)
                             = 100
                yV = - 100/4(-1)
                                                  yV = 25
                                                                        PV(- 5, 25)