Question

${x}^{2} - 7x + 3 = 0$
calcule em delta
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Answer 1

Explicação passo-a-passo:

$\sf x^2-7x+3=0$

$\sf \Delta=(-7)^2-4\cdot1\cdot3$

$\sf \Delta=49-12$

$\sf \Delta=37$

$\sf x=\dfrac{-(-7)\pm\sqrt{37}}{2\cdot1}=\dfrac{7\pm\sqrt{37}}{2}$

$\sf x'=\dfrac{7+\sqrt{37}}{2}$

$\sf x'=\dfrac{7-\sqrt{37}}{2}$