Question

5 - Encontre as raízes reais da
equação abaixo. *
-x² + 3x + 10=0​

Answer 1

• $\small{\sf{-x^{2}+3x+10=0}}$

◼️Coeficientes

• $\sf{a=-1}$

• $\sf{b=+3}$

• $\sf{c=+10}$

◼️Discriminante

• $\small{\sf{\Delta=b^{2}-4.a.c}}$

• $\sf{\Delta=(3)^{2}-4.(-1).(10)}$

• $\sf{\Delta=9+40}$

• $\sf{∆=49}$

◼️Raízes da equação

• $\small{\sf{x'=[-(3)+\sqrt{49}]/2.(-1)}}$

• $\sf{x'=[-3+7]/-2}$

• $\sf{x'=4/-2}$

• $\red{\boxed{\sf{x'=-2}}}$

• $\small{\sf{x"=[-(3)-\sqrt{49}]/2.(-1)}}$

• $\sf{x"=[-3-7]/-2}$

• $\sf{x"=-10/-2}$

• $\red{\boxed{\sf{x"=+5}}}$

◼️ As raízes reais serão : -2 e 5