Question

(2/3)^3x+1 =1  como faz isso ? 

Answer 1

$\frac{2}{3}^{3x+1} = 1 \\ \\ log \frac{2}{3}^{3x+1} = log1 \\ \\ (3x+1).(log( \frac{2}{3} )) = 0 \\ \\ 3x + 1 = 0 \\ \\ 3x = -1 \\ \\ x = \frac{-1}{3}$

Answer 2

$\left(\frac{2}{3}\right)^{3x+1}=1\\\\\left(\frac{2}{3}\right)^{3x+1}=\left(\frac{2}{3}\right)^0\\\\3x+1=0\\\\3x=-1\\\\\boxed{x=\frac{-1}{3}}$