• Matéria: Química
  • Autor: rlayane270
  • Perguntado 5 anos atrás

faça distribuição eletrônica dos elementos a seguir

22Ti

74W

37Rb

75Re

25Mn

43Tc

20 Ca

35 Br

2He

15p

83Bi

31Ga

83Po

10Ne

30Zn

27Co

12Mg

55Cs

79Au

5B

13AL

17Cl

36Kr

3Li

72Hf

109Mt


Respostas

respondido por: rick160163
0

Resposta:Segue as respostas abaixo na explicação aplicando o Diagramas de Linus Pauling

Explicação:

22Ti -->1s2,2s2,2p6,3s2,3p6,4s2,3d2

74W---> 1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d4

37Rb -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s1

75Re --> 1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d5

25Mn -->1s2,2s2,2p6,3s2,3p6,4s2,3d5

20 Ca -->1s2,2s2,2p6,3s2,3p6,4s2

35 Br --> 1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p5

2He -->1s2

15P--> 1s2,2s2,2p6,3s2,3p3

83Bi -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d10,6p3

31Ga --> 1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p1

84Po -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d10,6p4

10Ne -->1s2,2s2,2p6

27Co -->1s2,2s2,2p6,3s2,3p6,4s2,3d7

12Mg -->1s2,2s2,2p6,3s2

55Cs -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s1

79Au --> 1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d9

5B -->1s2,2s2,2p1

13AL -->1s2,2s2,2p6,3s2,3p1

17Cl--> 1s2,2s2,2p6,3s2,3p5

36Kr -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6

3Li -->1s2,2s1

72Hf -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d2

109Mt -->1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p6,5s2,4d10,5p6,6s2,4f14,5d10,6p6,7s2,5f14,6d7

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