Question

x²-6×+5=0

ajudem pfvr​

Answer 1

Resposta:

∆= b²-4ac

∆= 6²-4(-1)(-5)

∆= 36-20

∆= 16

x=-b±√∆/2a

x=-6±√16/2(-1)

x'=-6+4/-2

x'= -2/-2

x'= 1

x"= -6-4/-2

x"= -10/-2

x"= 5

Explicação passo-a-passo:

Answer 2

x²-6×+5=0

x² - x - 5x + 5 = 0

x . (x - 1) - 5 (x - 1) = 0

(x - 1) . (x - 5) = 0

x - 1 = 0

x - 5 = 0

x' = 1, x" = 5