• Matéria: Matemática
  • Autor: dieneferbarbosa
  • Perguntado 6 anos atrás

{[(8*4+3)+7+(3+15+5)x3]x2-(19-7) +6} x 2+12=

Respostas

respondido por: claudiacrispim
1

{[(8*4+3)+7+(3+15+5)x3]x2-(19-7) +6} x 2+12=

{[(32+3)+7+(18+5)×3]×2-12+6}×2+12=

{[35+7+23×3]×2-13+6}×2+12=

{[35+7+69]×2-13+6}×2+12=

{111×2-13+6}×2+12=

{222-13+6}×2+12=

215×2+12=

430+12=

442

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