Question

integral de x^-3 dx
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Answer 1

$\int\: {x}^{ - 3}dx = {x}^{ - 3 + 1} = \frac{ {x}^{ - 2} }{ - 2} = - \frac {1}{2 {x}^{2} }$

Resposta:

$- \frac{1}{ 2{x}^{2} } + c$