Question

substitua os valores x=0 x=1 e x=1 sobre 2

Answer 1

f(x) = $\frac{5x^2}{6} - 7x + \frac{4}{3}$

f(0) = 0 - 0 + 4/3
f(0) = 4/3

f(1) = 5/6 - 7 + 4/3
f(1) = (5 - 42 + 8)/6
f(1) = -29/6

f(1/2) = 5/6.1/4 - 7.1/2 + 4/3
f(1/2) = 5/24 - 7/2 + 4/3
f(1/2) = (5 - 84 + 32)/24
f(1/2) = -47/24

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