Question

como resolver essa equaçao do 2 grau na formula de bhaskara
x²-13+12=0

Answer 1

x^2-13x+12=0
delta=b^2-4ac
delta=(-13)^2-4.1.12
delta=169-48
delta=121
x=-b-/+ raiz de delta/2a
x=-(-13)-11/2.1
x=13-11/2
x=2/2
x=1
x=-(-13)+11/2.1
x=13+11/2
x=24/2
x=12
S={1, 12}