Question

Calcule f(10) sendo f(t)= -5t² +200.

f(10)= +300

f(10)= 300

f(10)= -300

f(10)= -200​

Answer 1

Resposta:

f(10) = - 300

Explicação passo-a-passo:

f(t) = - 5t² + 200

f(t) = - 5t² + 200f(10) = - 5 . 10² + 200

f(t) = - 5t² + 200f(10) = - 5 . 10² + 200f(10) = - 5 . 100 + 200

f(t) = - 5t² + 200f(10) = - 5 . 10² + 200f(10) = - 5 . 100 + 200f(10) = - 500 + 200

f(t) = - 5t² + 200f(10) = - 5 . 10² + 200f(10) = - 5 . 100 + 200f(10) = - 500 + 200f(10) = - 300