Question

10- dada as matrizes

A= { 1 4 0} B={ 1 4 0}
{-2 4 3} {-2 4 3}

C= { 1 4 0} D= { 1 4 0}
{ -2 4 3} {-2 4 3}

CALCULE=

a) 2a
b) -5b
c) 8c
d) 3d - 2b​

Answer 1

Caso tenha problemas para visualizar a resposta experimente abrir pelo navegador https://brainly.com.br/tarefa/33744638?answering=true&answeringSource=feedPublic%2FhomePage%2F12

===========================================================

$\tt{a)}~\sf{2A}=2\cdot\begin{bmatrix}\sf{1}&\sf{4}&\sf{0}\\\sf{-2}&\sf{4}&\sf{3}\end{bmatrix}=\begin{bmatrix}\sf{2}&\sf{8}&\sf{0}\\\sf{-4}&\sf{8}&\sf{6}\end{bmatrix}$

$\tt{b)}~\sf{-5B}=\sf{-5}\cdot\begin{bmatrix}\sf{1}&\sf{4}&\sf{0}\\\sf{-2}&\sf{4}&\sf{3}\end{bmatrix}=\begin{bmatrix}\sf{-5}&\sf{-20}&\sf{0}\\\sf{10}&\sf{-20}&\sf{-15}\end{bmatrix}$

$\tt{c)}~\sf{8C}=\sf{8}\cdot\begin{bmatrix}\sf{1}&\sf{4}&\sf{0}\\\sf{-2}&\sf{4}&\sf{3}\end{bmatrix}=\begin{bmatrix}\sf{8}&\sf{32}&\sf{0}\\\sf{-16}&\sf{32}&\sf{24}\end{bmatrix}$

$\tt{d)}\\\sf{3D}=3\cdot\begin{bmatrix}\sf{1}&\sf{4}&\sf{0}\\\sf{-2}&\sf{4}&\sf{3}\end{bmatrix}=\begin{bmatrix}\sf{3}&\sf{12}&\sf{0}\\\sf{-6}&\sf{12}&\sf{9}\end{bmatrix}\\\sf{2B}=2\cdot\begin{bmatrix}\sf{1}&\sf{4}&\sf{0}\\\sf{-2}&\sf{4}&\sf{3}\end{bmatrix}=\begin{bmatrix}\sf{2}&\sf{8}&\sf{0}\\\sf{-4}&\sf{8}&\sf{6}\end{bmatrix}$

$\sf{3D-2B}=\begin{bmatrix}\sf{3}&\sf{12}&\sf{0}\\\sf{-6}&\sf{12}&\sf{9}\end{bmatrix}-\begin{bmatrix}\sf{2}&\sf{8}&\sf{0}\\\sf{-4}&\sf{8}&\sf{6}\end{bmatrix}=\begin{bmatrix}\sf{1}&\sf{4}&\sf{0}\\\sf{-2}&\sf{4}&\sf{3}\end{bmatrix}$