• Matéria: Matemática
  • Autor: brunogiga1236
  • Perguntado 5 anos atrás

Calcule as integrais usando fracões parciais

Anexos:

Respostas

respondido por: CyberKirito
0

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\sf{\dfrac{x+4}{x^2+5x-6}=\dfrac{x+4}{(x-1)(x+6)}=\dfrac{A}{x-1}+\dfrac{B}{x+6}}

\sf{A=\dfrac{x+4}{x+6}\Bigg|_{x=1}=\dfrac{5}{7}}\\\sf{B=\dfrac{x+4}{x-1}\Bigg|_{x=-6}=\dfrac{2}{7}}

\displaystyle\sf{\int\dfrac{x+4}{x^2+5x-6}~dx=\dfrac{5}{7}\int\dfrac{dx}{x-1}+\dfrac{2}{7}\int\dfrac{dx}{x+6}}\\\sf{\dfrac{5}{7}\ell n|x-1|+\dfrac{2}{7}\ell n|x+6|+k}

\displaystyle\sf{\int\dfrac{x+4}{x^2+5x-6}~dx=\ell n\left|([x-1]^5\cdot[x+6]^2)^{\frac{1}{7}}\right|+k}

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