Qual a taxa de um aplicação de R$10.000,00, por 08 meses, chegando um montante de R$ 14.000,00, no regime de juros compostos.
Respostas
respondido por:
2
montante=M=14000
capital=C=10000
periodo=n=8
i=taxa=?
M=C*(1+i)^n
14000=10000(1+i)^8
14000/10000=(1+i)^8
1,4=(1+i)^8
log(1,4)=8*log(1+i)
0,14613=8LOG(1+i)
0,14613/8=log(1+i)
0,01827=log(1+i)
log(1+i)=0,01827
(1+i)=10^0,01827
(1+i)=1,04296
i=1,04296-1
i=0,04296 ou 4,296%a.m.
capital=C=10000
periodo=n=8
i=taxa=?
M=C*(1+i)^n
14000=10000(1+i)^8
14000/10000=(1+i)^8
1,4=(1+i)^8
log(1,4)=8*log(1+i)
0,14613=8LOG(1+i)
0,14613/8=log(1+i)
0,01827=log(1+i)
log(1+i)=0,01827
(1+i)=10^0,01827
(1+i)=1,04296
i=1,04296-1
i=0,04296 ou 4,296%a.m.
respondido por:
1
Taxa (i): ?
Capital (C): 10.000,00
Prazo (n): 8 meses
Montante (M): 14.000,00
![M=C(1+i)^n\\\\14000=10000(1+i)^8\\\\(1+i)^8=1,4\\\\(1+i)=\sqrt[8]{1,4}\\\\1+i=1,0429\\\\\boxed{i=0,043}](https://tex.z-dn.net/?f=M%3DC%281%2Bi%29%5En%5C%5C%5C%5C14000%3D10000%281%2Bi%29%5E8%5C%5C%5C%5C%281%2Bi%29%5E8%3D1%2C4%5C%5C%5C%5C%281%2Bi%29%3D%5Csqrt%5B8%5D%7B1%2C4%7D%5C%5C%5C%5C1%2Bi%3D1%2C0429%5C%5C%5C%5C%5Cboxed%7Bi%3D0%2C043%7D "M=C(1+i)^n\\\\14000=10000(1+i)^8\\\\(1+i)^8=1,4\\\\(1+i)=\sqrt[8]{1,4}\\\\1+i=1,0429\\\\\boxed{i=0,043}")
Isto é, 4,3% a.m
Capital (C): 10.000,00
Prazo (n): 8 meses
Montante (M): 14.000,00
Isto é, 4,3% a.m
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