Question

como resolve essa equacao 2x²-7x+2=0?

Answer 1

$a = 2 \ b = -7 \ c=2\\\\x=\frac{-b\± \sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-7)\± \sqrt{(-7)^2-4*2*2}}{2*2}\\\\x=\frac{7\± \sqrt{33}}{4}$

Answer 2

2x²-7x+2=0

a = 2       b = - 7       c = +2
Δ = b² - 4.a.c
Δ = (-7)² -4.(2).(+2)
Δ = + 49 - 16
Δ = 33

x = - b ± √Δ
          2.a

x = - (-7) ± √33
            2.2

x = + 7 ± √33 
           4

x'= 7 + √33
          4         

x"= 7 -√33   =
        4          

S[(7-√33/4) , (7+√33)/4]