Question

URGENTEEE determine o 3° termo no desenvolvimento de (2x+2)^4

a)69x^2
b)16x^2
c)96x^2

OBS.: Potência : ^​

Answer 1

Explicação passo-a-passo:

O termo geral é:

$\sf T_{p+1}=\dbinom{4}{p}\cdot(2x)^{4-p}\cdot2^p$

O 3° termo é:

$\sf T_{2+1}=\dbinom{4}{2}\cdot(2x)^{4-2}\cdot2^2$

$\sf T_{3}=\dfrac{4\cdot3}{2}\cdot(2x)^{2}\cdot2^2$

$\sf T_{3}=\dfrac{12}{2}\cdot4x^2\cdot4$

$\sf T_{3}=6\cdot4x^2\cdot4$

$\sf T_{3}=24x^2\cdot4$

$\sf \red{T_{3}=96x^2}$

Letra C