Question

escreva a fração irredutível de cada fração dada

9/45

49/56

19/133

77/88

96/48

18/81

45/10

21/36

16/48

45/80

6/48

36/60

99/45

55/240

34/14

33/27

121/55

64/56

20/140

2/4

54/42

63/119

32/104

39/26

ajudem por favor
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Answer 1

Explicação passo-a-passo:

a) $\sf \dfrac{9}{45}=\dfrac{9\div9}{45\div9}=\red{\dfrac{1}{5}}$

b) $\sf \dfrac{49}{56}=\dfrac{49\div7}{56\div7}=\red{\dfrac{7}{8}}$

c) $\sf \dfrac{19}{133}=\dfrac{19\div19}{133\div19}=\red{\dfrac{1}{7}}$

d) $\sf \dfrac{77}{88}=\dfrac{77\div11}{88\div11}=\red{\dfrac{7}{8}}$

e) $\sf \dfrac{96}{48}=\dfrac{96\div48}{48\div48}=\dfrac{2}{1}=\red{2}$

f) $\sf \dfrac{18}{81}=\dfrac{18\div9}{81\div9}=\red{\dfrac{2}{9}}$

g) $\sf \dfrac{45}{10}=\dfrac{45\div5}{10\div5}=\red{\dfrac{9}{2}}$

h) $\sf \dfrac{21}{36}=\dfrac{21\div3}{36\div3}=\red{\dfrac{7}{12}}$

i) $\sf \dfrac{16}{48}=\dfrac{16\div16}{48\div16}=\red{\dfrac{1}{3}}$

j) $\sf \dfrac{45}{80}=\dfrac{45\div5}{80\div5}=\red{\dfrac{9}{16}}$

k) $\sf \dfrac{6}{48}=\dfrac{6\div6}{48\div6}=\red{\dfrac{1}{8}}$

l) $\sf \dfrac{36}{60}=\dfrac{36\div12}{60\div12}=\red{\dfrac{3}{5}}$

m) $\sf \dfrac{99}{45}=\dfrac{99\div9}{45\div9}=\red{\dfrac{11}{5}}$

n) $\sf \dfrac{55}{240}=\dfrac{55\div5}{240\div5}=\red{\dfrac{11}{48}}$

o) $\sf \dfrac{34}{14}=\dfrac{34\div2}{14\div2}=\red{\dfrac{17}{7}}$

p) $\sf \dfrac{33}{27}=\dfrac{33\div3}{27\div3}=\red{\dfrac{11}{9}}$

q) $\sf \dfrac{121}{55}=\dfrac{121\div11}{55\div11}=\red{\dfrac{11}{5}}$

r) $\sf \dfrac{64}{56}=\dfrac{64\div8}{56\div8}=\red{\dfrac{8}{7}}$

s) $\sf \dfrac{20}{140}=\dfrac{20\div20}{140\div20}=\red{\dfrac{1}{7}}$

t) $\sf \dfrac{2}{4}=\dfrac{2\div2}{4\div2}=\red{\dfrac{1}{2}}$

u) $\sf \dfrac{54}{42}=\dfrac{54\div6}{42\div6}=\red{\dfrac{9}{7}}$

v) $\sf \dfrac{63}{119}=\dfrac{63\div7}{119\div7}=\red{\dfrac{9}{17}}$

w) $\sf \dfrac{32}{104}=\dfrac{32\div8}{104\div8}=\red{\dfrac{4}{13}}$

x) $\sf \dfrac{39}{26}=\dfrac{39\div13}{26\div13}=\red{\dfrac{3}{2}}$