Question

Resolva as equações de primeiro grau com incognita ;
A)3x100=2x+100+200

B)y+500+250=4y

C)3b+500=1000+500+b+100

D)2c+500=x+b+x

Answer 1

B) y+500+250=4y
4y-y=750
3y=750
y=750/3
y=250

C) 3b+500=1000+500+b+100
     3b-b=1000+500+100-500
     2b=1100
     b=1100/2
     b=550