• Matéria: Matemática
  • Autor: Tatazim
  • Perguntado 9 anos atrás

Calcule as seguinte contas:

Anexos:

LuanaSC8: Qual é o sinal entre a fração e (-2)^-1 na letra B)?
Tatazim: - (negativo)

Respostas

respondido por: LuanaSC8
0
a)~~0^{25}+(-25)^0+(-1)^4\to~~0+1+(+1)\to~~0+1+1\to \boxed{2}\\\\\\\\b)~~ (-1)^3+\left(- \dfrac{1}{2} \right)^{-1}- (-2)^{-1}\to~~-1+(-2)^1-\left(- \dfrac{1}{2} \right)^1\to\\\\\\ -1-2+ \dfrac{1}{2}\to~~ \dfrac{-2-4+1}{2}\to~~ \boxed{- \dfrac{5}{2}}




c)~~ \dfrac{10^{-1}}{5^{-1}+2^{-1}} \to~~ \dfrac{\dfrac{1}{10}^1 }{\dfrac{1}{5}^1 +\dfrac{1}{2} ^1 } \to~~ \dfrac{\dfrac{1}{10} }{\dfrac{1}{5} +\dfrac{1}{2} } \to~~ \dfrac{\dfrac{1}{10} }{\dfrac{2+5}{10} } \to~~ \dfrac{\dfrac{1}{10} }{\dfrac{7}{10} } \to\\\\\\  \dfrac{1}{10}\times \dfrac{10}{7}\to~~ \dfrac{10}{70}\to~~ \boxed{\dfrac{1}{7}}





d)~~ \dfrac{4^2-4^{-2}}{4^2+4^{-2}} \to~~ \dfrac{4^2-\dfrac{1}{4}^2 }{4^2+\dfrac{1}{4}^2 } \to~~ \dfrac{16-\dfrac{1}{16} }{16+\dfrac{1}{16} } \to~~ \dfrac{\dfrac{256-1}{16} }{\dfrac{256+1}{16} } \to~~ \dfrac{\dfrac{255}{16} }{\dfrac{257}{16} } \to\\\\\\ \dfrac{255}{16}\times\dfrac{16}{257}\to~~ \dfrac{4080}{4112}\to~~ \boxed{\dfrac{255}{257}}





e)~~ \dfrac{8^{-2}-4^{-2}}{8^{-1}-4^{-1}} \to~~ \dfrac{ \dfrac{1}{8} ^2-\dfrac{1}{4}^2 }{ \dfrac{1}{8} ^1-\dfrac{1}{4}^1} \to~~ \dfrac{ \dfrac{1}{64} -\dfrac{1}{16} }{ \dfrac{1}{8} -\dfrac{1}{4}} \to~~ \dfrac{ \dfrac{1-4}{64} }{ \dfrac{1-2}{8} } \to~~ \dfrac{ \dfrac{-3}{64} }{ \dfrac{-1}{8} } \to\\\\\\ \dfrac{-3}{64}\times \left(\dfrac{-8}{1}\right)\to~~ +\dfrac{24}{64}\to~~ \boxed{ \frac{3}{8} }



A que tem o Maior Valor é a expressão da letra D). E a que tem Menor valor é a letra B).
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