Question

dada cos x= 4÷5 , com 0 < x<π÷2 , calcule sen x e tg x.

Answer 1

Resposta:

Explicação passo-a-passo:

cos x= 4/5

senx² = 1- cosx²

senx² = 1- (4/5)²

senx²= 1 -16/25

senx²= 25/25 - 16/25

senx²= 9/25

senx= √9/√25

senx = 3/5

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tgx = senx /cosx

tgx = 3/5 : 4/5

tgx = 3/5 * 5/4

tgx = 15/20

tgx = 3/4