Question

Se log a = 2, log b = 3 e log c = 4, determine:

Answer 1

Resposta:

log c²b/a⁴

=log c²b  - log a⁴

=log c² + log b -log a⁴

= 2 * log c + log b - 4 * log a

= 2 * 4 + 3 - 4 * 2

= 8 +3 -8  = 3