Question

2x² – 3x + 1 = 0 S = {1,5}} baskara​

Answer 1

Explicação passo-a-passo:

$2 {x}^{2} - 3x + 1 = 0$

Sabendo o que

a = 2

b = -3

c = 1

=>Valor de ∆

$\sf ∆ = {b}^{2} - 4ac$

$\sf ∆ = {-3}^{2} - 4(2)(1)$

$\sf ∆ = 9 - 8$

$\sf ∆ = 1$

=>Valor de X

$x = \frac{ - ( - 3) </strong><strong>±</strong><strong> \sqrt{1} }{4}$

$x = \frac{3 </strong><strong>±</strong><strong> 1}{4}$

$x_{1} = \frac{3 + 1}{4} = > \frac{4}{4} = > 1$

$x_{2} = \frac{3 - 1}{4} = > \frac{2}{4} = > \frac{1}{2}$

$\sf S = \{ \frac{1}{2} \: ; \: 1 \}$

Espero ter ajudado !!!