Question

11. Dado log2=0,3, calcule log 400.
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Answer 1

$log 400=log4.100=log 2^2.10^2$

Propriedade 1:

$log(a.b)=loga+logb$

$=log2^2+log10^2$

Propriedade 2:

$log a^{n}=n.log a$

$=2.log2+2.log10=2.0,3+2.1=0,6+2$

$=2,6$