Question

Preciso de ajuda pf
1) Determine o valor de log32√2 + log2√32 :

Answer 1

log32√2 =x

32^x = √2

2^5x = 2¹/²

5x = 1/2

10x = 1

x = 1/10

log2√32 = y

2^y = √32

2^y = √2⁵

2^y = 2^5/2

y = 5/2 = 25/10

x+y = 1/10 + 25/10 = 26/10 = 13/5

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_{32}\:\sqrt{2} + log_2\:\sqrt{32}}$

$\mathsf{log_{2^5}\:2^{\frac{1}{2}} + log_2\:2^{\frac{5}{2}}}$

$\mathsf{\dfrac{1}{10}\:.\:log_{2}\:2 + \dfrac{5}{2}\:.\:log_2\:2}$

$\mathsf{log_{32}\:\sqrt{2} + log_2\:\sqrt{32} = \dfrac{1}{10} + \dfrac{5}{2}}$

$\boxed{\boxed{\mathsf{log_{32}\:\sqrt{2} + log_2\:\sqrt{32} = \dfrac{13}{5}}}}$