Question

Alguém me ajuda? Preciso isso o mais rápido possível!!!

Answer 1

a)

x²+x-6=0

x'=[-1+√(1+24)]/2 =(-1+5)/2=2

x''=[-1-√(1+24)]/2 =(-1-5)/2=-3

b)

x*(x-3)=28

x²-3x-28=0

x'=[3+√(9+112)]/2=(3+11)/2=7

x''=[3-√(9+112)]/2=(3-11)/2=-4

c)

7x²=4x+3

7x²-4x-3=0

x'=[4+√(16+84)]/14=(4+10)/14=1

x''=[4-√(16+84)]/14=(4-10)/14=-6/14=-3/7

d)

x/5 =(3-x²)/10

2x=3-x²

x²+2x-3=0

x'=[-2+√(4+12)]/2=(-2+4)/2=1

x''=[-2-√(4+12)]/2=(-2-4)/2=-3