• Matéria: Matemática
  • Autor: raissav640
  • Perguntado 5 anos atrás

complete a tabela seguir
opção A

× y=(×)= [×,f(×)]
0
1/2
1
2
3

Respostas

respondido por: arthurfranchilongen
0

× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3

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