Question

X⁴+20x²-3=0, respondam please.

Answer 1

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf x^4+20x^2-3=0$

• Substitua t por x²

$\sf t^2+20t-3=0$

$\sf t=\dfrac{-20\pm\sqrt{20^2-4\times1(-3)} }{2}$

$\sf t=\dfrac{-20\pm2\sqrt{103} }{2}$

$\sf t=\sqrt{103}-10 \\\\\sf t=-\sqrt{103}-10$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=-\sqrt{\sqrt{103}-10}\approx-0.385864698 } }}}\ \checkmark\\\\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \green{\sqrt{\sqrt{103}-108 }\approx0.38586469 }}}}\ \checkmark\\\\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \blue x=-i{\sqrt{\sqrt{103+10}}\approx-0-4.488751671i }}}}\ \checkmark$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \orange{ x=i \sqrt{\sqrt{103}+10} }\approx4.488751671i }}}\ \checkmark$←←↑↑ RESPOSTA.

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