Question

Me ajudem pf
(2x+y)(x-y)
(X²+3x-4) (x-2)
(c³+4c²+c) (c-1)

Answer 1

Resposta:

$(2x + y)( x - y) = \\ 2x \times x + 2x \times ( - y) + x \times y - y \times y = \\ 2x {}^{2} - 2xy + xy - y {}^{2} = \\ 2x {}^{2} - xy - y {}^{2}$

Explicação passo-a-passo:

$(x {}^{2} + 3x - 4)(x - 2) = \\ x {}^{2} \times x - 2x {}^{2} + 3x \times x - 2 \times 3x - 4 \times x + ( - 4) \times ( - 2) = \\ x {}^{3} - 2x {}^{2} + 3x {}^{2} - 6x - 4x + 8 = \\ x {}^{3} + x {}^{2} - 10x + 8$

$(c {}^{3} + 4c {}^{2} + c)(c - 1) = \\ c {}^{4} - c {}^{3} + 4c {}^{3} - 4c {}^{2} + c {}^{2} - 1c = \\ c {}^{4} + 3c {}^{3} -3c {}^{2} - 1c$