Question

1)Considerando log 2 = 0,3010 e log 3 = 0,4771, calcule:

a)log 8
b)log 12
c)log raiz quadrada de 2

Answer 1

$log8=log2^3=3.log2=3.(0,3010)=0,903$
$log12=log(2.2.3)=log2+log2+log3=0,3010+0,3010+0,4771=\\ 1,0791$
$log\sqrt2=log2^{\frac{1}{2}}=\frac{1}{2}log2=\frac{1}{2}.0,3010=0,1505$