Question

me ajudemm ai galera​

Answer 1

$\\ \\ \sf \: 7 {}^{5 - 11x} = 0 \\ \sf \: 2401 {}^{6 - 5x } = 0 \\ \\ \sf \: x \in Ø \\ \sf \: x \in Ø \\ \\ \sf \: \frac{49 {}^{3x - 5} }{7 {}^{5 - 11x} } = \frac{1}{2401 {}^{6 - 5x} },x\in \mathbb{R} \\ \\ \sf \: \frac{\Big(7 {}^{2}\Big) {}^{3x - 5} }{7 {}^{5 - 11x} } = \frac{1}{2401 {}^{6 - 5x} } \\ \\ \sf \: \frac{7 {}^{6x - 10} }{7 {}^{5 - 11x} } = \frac{1}{2401 {}^{6 - 5x} } \\ \\ \sf \: \frac{7 {}^{6x - 10} }{ {7}^{5 - 11x} } = \frac{1}{\Big(7 {}^{4} \Big) {}^{6 - 5x} } \\ \\ \sf \: \frac{7 {}^{6x - 10} }{7 {}^{5 - 11x} } = \Big(7 {}^{4} \Big) {}^{ - (6 - 5x)} \\ \\ \sf \: \frac{7 {}^{6x - 10} }{7 {}^{5 - 11x} } = 7 {}^{ - 24 + 20x} \\ \\ \sf \: 7 {}^{6x - 10 - (5 - 11x)} = 7 {}^{ - 24 + 20x} \\ \\ \sf \: 7 {}^{6x - 10 - 5 + 11x} = 7 {}^{ - 24 + 20x}\\ \\ \sf \: 7 {}^{17x - 10 - 5} = 7 {}^{ - 24 + 20x} \\ \\ \sf \: 7 {}^{17x - 15} = 7 {}^{ - 24 + 20x} \\ \\ \sf \: 17x - 15 = - 24 + 20x \\ \\ \sf \: 17x - 20x = - 24 + 15 \\ \\ \sf \: - 3x = - 24 + 15 \\ \\ \sf \: - 3x = -9 \\ \\ \sf \: x = - 9 \div - 3 \\ \\ \sf \: ( - ) \div ( - ) = ( + ) \\ \\ \sf \: x = 3$

Att: Nerd1990