Question

Resolva a equação: (4-i)z-(2+3i)=(8-5i)

Answer 1

$z(4-i)=(8-5i)+(2+3i)\\\\ z(4-i)=10-2i\\\\ z= \frac{10-2i}{4-i}\\\\ z= \frac{10-2i}{4-i}* \frac{4+i}{4+i} = \frac{40+10i-8i-2i^2}{16-(-1)} = \frac{42+2i}{17}$

$z=x+yi\\\\ x+yi=\frac{42+2i}{17} \\\\ \boxed{x= \frac{42}{17}} \\\\\ \boxed{y= \frac{2}{17}}$