Question

1. Determine as massas moleculares das substâncias abaixo:

a) N2

b) CO2

c) HNO3

d) H2SO4

e) C6H12O6

f) Ca(OH) 2

g) Ca(ClO3) 2

h) (NH4) 2SO4

i) Ca3 (PO4) 2

j) Al(OH) 3

Answer 1

Resposta:Segue as respostas abaixo na explicação

Explicação:

a) N2-->14x2-->28 g/mol

b) CO2-->12x1+16x2-->12+32-->44 g/mol

c) HNO3-->1x1+14x1+16x3-->1+14+48-->63 g/mol

d) H2SO4-->1x2+32x1+16x4-->2+32+64-->98 g/mol

e) C6H12O6-->12x6+1x12+16x6-->72+12+96-->180 g/mol

f) Ca(OH)2-->40x1+16x2+1x2-->40+32+2-->74 g/mol

g) Ca(ClO3)2-->40x1+35,5x2+16x6-->40+71+96-->207 g/mol

h) (NH4)2SO4-->14x2+1x8+32x1+16x4-->28+8+32+64-->132 g/mol

i) Ca3(PO4)2-->40x3+31x2+16x8-->120+62+128-->310 g/mol

j) Al(OH)3-->27x1+16x3+1x3-->27+48+3-->78 g/mol

Answer 2

Resposta:

a) N2 28 u

b) CO2. 12+32=44 u

c)HNO3 1+14+48= 63 u

d) H2SO4. 2+32+64=98 u

e)C6H12O6. 12×6+ 12+ 16×6= 180 u

Explicação:

f)Ca(OH)2. 40+16×2+2= 40+32+2=74 u

g)Ca(ClO3)2 40+36×2+16×6=40+72+96= 208 u

h)(NH4)2SO4 14×2+8+32+ 16×4=28+8+32+64=132u

i)Ca3(PO4)2 40×3+ 31×2+ 16×8= 120+62+ 128= 310u

j)Al(OH)3. 27+ 16×3+ 3= 27+48+3=78 u