Question

resolva as equações literais​

Answer 1

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$\tt c)~\sf 2x-24a=8x\implies 8x=2x-24a\\\sf 8x-2x=-24a\\\sf 6x=-24a\\\sf x=-\dfrac{24a}{6}\\\sf x=-4a\checkmark\\\tt d)~\sf 8x+7b=2x+25b\\\sf8x-2x=24b-7b\\\sf6x=17b\\\sf x=\dfrac{17b}{6}\checkmark\\\tt g)~\sf3ax=9\\\sf x=\dfrac{9\div3}{3a\div3}\\\sf x=\dfrac{3}{a}\checkmark$

$\tt h)~\sf\dfrac{a+x}{3}-a=\dfrac{2a-x}{2}\cdot6\\\sf 2\cdot(a+x)-6a=3\cdot(2a-x)\\\sf 2a+2x-6a=6a-3x\\\sf 2x+3x=6a+6a-2a\\\sf 5x=10a\\\sf x=\dfrac{10a}{5}\\\sf x=2a\checkmark$

$\tt i)~\sf 2bx=-12\\\sf x=-\dfrac{12\div2}{2b\div2}\\\sf x=-\dfrac{6}{b}\checkmark\\\tt j)~\sf 5x+m=4m\\\sf 5x=4m-m\\\sf5x=3m\\\sf x=\dfrac{3m}{5}\checkmark$