Question

Aplicando o teorema de tales, calcule o valor de x​

Answer 1

(2x+2)/6x = (2x+4)/(2x+12)

12x^2+24x = 4x^2 + 24x + 4x + 24

8x^2 - 4x - 24 = 0 (÷4)

2x^2 - x - 6 = 0

delta = (-1)^2 - 4.2.(-6)

delta = 49

x = 1 + -√49/2.2

x = 1 + - 7 / 4

x' = 1 + 7 / 4 = 2

x" = 1 - 7 / 4 = -6/4 ( ñ vale valor negativo)

Logo , o valor de x = 2.