• Matéria: Matemática
  • Autor: rafael2114
  • Perguntado 5 anos atrás

a) 80 + 5+[(8+ 12 ) + ( 13 + 12 )] + 10 ) =
b) 58 +[ 48 - (31 - 10 ) +15) =
c) 38 - ((51 - 15 ) + [5+(3-1)1-10) =
d) [9+ (585 - 15 x 6)] = 56 =
e) (30-(17-8)x3 +25] = 7 =
f) {[(8x4+3)=7+(3+15=51x3] x2-(19-7)=6)x2 + 12 =​

Respostas

respondido por: elealdosagitario
4

Resposta:

a)140

b)90

c)5

d)448

e)21

f)572

Explicação passo-a-passo:

a) 80+5+[20+25]+10)

80+5+45+10

140

b)58+[48-21+15]

58+[53-21]

58+32

90

c) 38-(36+[5+(2)1-10])

38-(36+[5+2-10])

38-(36+[7-10])

38-(36+[-3])

38-(36-3)

38-(+33)

38-33

5

d) [9+ (585 - 15 x 6)] =56

[9+(585-90)]-56

9+495-56

504-56

448

e)(30-(17-8)x3 +25)=7

(30-(+9)x3+25)-7

(30-(+27)+25)-7

30-27+25-7

55-34

21

f) {[(8x4+3)=7+(3+15=51x3) x2-(19-7)=6]x2 + 12}

{[(32+3)=7+(3+15=153]x2-12=6]x2+12}

{[35=7+(18-153)x2-12-6]x2+12}

{[35-7+(-135)x2-12-6]x2+12}

{[28+(+270)-12-6]x2+12}

{[28+270-12-6]x2+12}

{[298-18]x2+12}

{280x2+12}

560+12

572


carlianodias4566: obrigado
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